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Question 24
Solve the system.- x−y+z=1x+y+z=3x+y−z=−3\begin{array} { l } x - y + z = 1 \\x + y + z = 3 \\x + y - z = - 3\end{array}x−y+z=1x+y+z=3x+y−z=−3
A) {(3,−1,1) }\{ ( 3 , - 1,1 ) \}{(3,−1,1) } B) ∅\varnothing∅ C) {(−1,1,3) }\{ ( - 1,1,3 ) \}{(−1,1,3) } D) {(−1,3,1) }\{ ( - 1,3,1 ) \}{(−1,3,1) }
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