Solve the problem.
-Find the equation of a circle in standard form with center at the point (-3, 2) and tangent to the line y = 4.
A) $( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16$
B) $( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 16$
C) $( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 4$
D) $( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 4$

Question

Solve the problem.
-Find the equation of a circle in standard form with center at the point (-3, 2) and tangent to the line y = 4. 
A) $( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16$
B) $( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 16$
C) $( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 4$
D) $( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 4$

Quizplus · Accepted Answer

The distance from the center (-3, 2) to the line y = 4 is 2, which is the radius. The equation of the circle is $(x + 3)^2 + (y - 2)^2 = 4$.

Solve the Problem (x+3)2+(y−2)2=16( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16(x+3)2+(y−2)2=16

Solve the Problem $( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16$