Solve the problem.
-Find the equation of a circle in standard form where C(6, -2) and D(-4, 4) are endpoints of a diameter.
A) $( x + 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 136$
B) $( x + 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 34$
C) $( x - 1 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 34$
D) $( x - 1 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 136$

Question

Quizplus · Accepted Answer

The Answer of Solve the problem.
-Find the equation of a circle in standard form where C(6, -2) and D(-4, 4) are endpoints of a diameter.
A) $( x + 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 136$
B) $( x + 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 34$
C) $( x - 1 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 34$
D) $( x - 1 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 136$

Solve the Problem (x+1)2+(y+1)2=136( x + 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 136(x+1)2+(y+1)2=136

Solve the Problem $( x + 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 136$