Find the distance d( $$\mathrm { d } \left( \mathrm { P } _ { 1 } , \mathrm { P } _ { 2 } \right) \text { between the points } \mathrm { P } _ { 1 } \text { and } \mathrm { P } _ { 2 }$$ .
-$$\mathrm { P } _ { 1 } = ( - 3 , - 1 ) ; \mathrm { P } _ { 2 } = ( 5,3 )$$
A) 48
B) $4 \sqrt { 5 }$
C) 4
D) $48 \sqrt { 3 }$

Question

Quizplus · Accepted Answer

The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ in a plane is given by the formula $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$. Applying this formula to the given points $(-3, -1)$ and $(5, 3)$, we get $\sqrt{(5 - (-3))^2 + (3 - (-1))^2} = \sqrt{8^2 + 4^2} = \sqrt{64 + 16} = \sqrt{80} = 4\sqrt{5}$.

Find the Distance D - P1=(−3,−1);P2=(5,3)\mathrm { P } _ { 1 } = ( - 3 , - 1 ) ; \mathrm { P } _ { 2 } = ( 5,3 )P1​=(−3,−1);P2​=(5,3)

Find the Distance D
- $\mathrm { P } _ { 1 } = ( - 3 , - 1 ) ; \mathrm { P } _ { 2 } = ( 5,3 )$