Find the distance d( $$\mathrm { d } \left( \mathrm { P } _ { 1 } , \mathrm { P } _ { 2 } \right) \text { between the points } \mathrm { P } _ { 1 } \text { and } \mathrm { P } _ { 2 }$$ .
-$$\mathrm { P } _ { 1 } = ( 6,1 ) ; \mathrm { P } _ { 2 } = ( - 2 , - 2 )$$
A) 5
B) $\sqrt { 55 }$
C) 24
D) $\sqrt { 73 }$

Question

Quizplus · Accepted Answer

The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$. Substituting the given points, we get $\sqrt{(-2 - 6)^2 + (-2 - 1)^2} = \sqrt{(-8)^2 + (-3)^2} = \sqrt{64 + 9} = \sqrt{73}$.

Find the Distance D - P1=(6,1);P2=(−2,−2)\mathrm { P } _ { 1 } = ( 6,1 ) ; \mathrm { P } _ { 2 } = ( - 2 , - 2 )P1​=(6,1);P2​=(−2,−2)

Find the Distance D
- $\mathrm { P } _ { 1 } = ( 6,1 ) ; \mathrm { P } _ { 2 } = ( - 2 , - 2 )$