Solve the problem.
-A rocket is shot straight up in the air from the ground at a rate of 80 feet per second. The rocket is tracked by a range finder that is 431 feet from the launch pad. Let d represent the distance from the rocket to the range finder
And t represent the time, in seconds, since "blastoff". Express d as a function of t.
A) $\mathrm { d } ( \mathrm { t } ) = 431 ^ { 2 } + ( 80 \mathrm { t } ) ^ { 2 }$
B) $d ( t ) = \sqrt { 80 ^ { 2 } + ( 431 t ) ^ { 2 } }$
C) $\mathrm { d } ( \mathrm { t } ) = 431 + 80 \mathrm { t } ^ { 2 }$
D) $\mathrm { d } ( \mathrm { t } ) = \sqrt { 431 ^ { 2 } + ( 80 \mathrm { t } ) ^ { 2 } }$

Question

Quizplus · Accepted Answer

The distance $d(t)$ from the rocket to the range finder can be found using the Pythagorean theorem, where one leg is the constant distance of 431 feet from the launch pad to the range finder, and the other leg is the vertical distance the rocket has traveled, $80t$. Thus, $d(t) = \sqrt{431^2 + (80t)^2}$.

Solve the Problem d(t)=4312+(80t)2\mathrm { d } ( \mathrm { t } ) = 431 ^ { 2 } + ( 80 \mathrm { t } ) ^ { 2 }d(t)=4312+(80t)2

Solve the Problem $\mathrm { d } ( \mathrm { t } ) = 431 ^ { 2 } + ( 80 \mathrm { t } ) ^ { 2 }$