Solve the problem.
-The height s of a ball (in feet) thrown with an initial velocity of 60 feet per second from an initial height of 4 feet is given as a function of time $t$ (in seconds) by $\mathrm { s } ( \mathrm { t } ) = - 16 \mathrm { t } ^ { 2 } + 60 \mathrm { t } + 4$. What is the maximum height? Round to the nearest hundredth, if necessary.

A) -37.25 ft
B) 60.25 ft
C) 69.63 ft
D) 56.5 ft

Question

Solve the problem.
-The height s of a ball (in feet) thrown with an initial velocity of 60 feet per second from an initial height of 4 feet is given as a function of time $t$ (in seconds) by $\mathrm { s } ( \mathrm { t } ) = - 16 \mathrm { t } ^ { 2 } + 60 \mathrm { t } + 4$. What is the maximum height? Round to the nearest hundredth, if necessary.

A) -37.25 ft 
B) 60.25 ft 
C) 69.63 ft 
D) 56.5 ft

Quizplus · Accepted Answer

The Answer of Solve the problem.
-The height s of a ball (in feet) thrown with an initial velocity of 60 feet per second from an initial height of 4 feet is given as a function of time $t$ (in seconds) by $\mathrm { s } ( \mathrm { t } ) = - 16 \mathrm { t } ^ { 2 } + 60 \mathrm { t } + 4$. What is the maximum height? Round to the nearest hundredth, if necessary.

A) -37.25 ft 
B) 60.25 ft 
C) 69.63 ft 
D) 56.5 ft

Solve the Problem ttt (In Seconds) By s(t)=−16t2+60t+4\mathrm { s } ( \mathrm { t } ) = - 16 \mathrm { t } ^ { 2 } + 60 \mathrm { t } + 4s(t)=−16t2+60t+4

Solve the Problem $t$ (In Seconds) By $\mathrm { s } ( \mathrm { t } ) = - 16 \mathrm { t } ^ { 2 } + 60 \mathrm { t } + 4$