Find the domain of the function.
-$$f ( x ) = \frac { x } { x ^ { 2 } + 14 }$$
A) $\{ x \mid x \neq - 14 \}$
B) $\{ x \mid x - 14 \}$
C) $\{ x \mid x \neq 0 \}$
D) all real numbers

Question

Find the domain of the function.
-$$f ( x ) = \frac { x } { x ^ { 2 } + 14 }$$
A) $\{ x \mid x \neq - 14 \}$
B) $\{ x \mid x > - 14 \}$
C) $\{ x \mid x \neq 0 \}$
D) all real numbers

Quizplus · Accepted Answer

The domain of the function $f(x) = \frac{x}{x^2 + 14}$ includes all real numbers because the denominator $x^2 + 14$ can never be zero (since $x^2$ is always non-negative, adding 14 ensures the denominator is always positive).

Find the Domain of the Function f(x)=xx2+14f ( x ) = \frac { x } { x ^ { 2 } + 14 }f(x)=x2+14x​

Find the Domain of the Function $f ( x ) = \frac { x } { x ^ { 2 } + 14 }$