Use Cramer's rule to solve the linear system.
-$$\left\{ \begin{array} { l }
4 x - 7 y = 5 \
2 x + 5 y = - 3
\end{array} \right.$$

A) $x = - \frac { 2 } { 17 } , y = \frac { 11 } { 17 }$

B) $x = \frac { 23 } { 3 } , y = - \frac { 11 } { 3 }$

C) $x = \frac { 2 } { 17 } , y = - \frac { 11 } { 17 }$

D) $x = \frac { 2 } { 3 } , y = \frac { 1 } { 3 }$

Question

Use Cramer's rule to solve the linear system.
-$$\left\{ \begin{array} { l } 
4 x - 7 y = 5 \
2 x + 5 y = - 3
\end{array} \right.$$

A) $x = - \frac { 2 } { 17 } , y = \frac { 11 } { 17 }$

B) $x = \frac { 23 } { 3 } , y = - \frac { 11 } { 3 }$

C) $x = \frac { 2 } { 17 } , y = - \frac { 11 } { 17 }$

D) $x = \frac { 2 } { 3 } , y = \frac { 1 } { 3 }$

Quizplus · Accepted Answer

Cramer's rule involves calculating determinants. The determinant of the coefficient matrix is 4(5) - (-7)(2) = 20 + 14 = 34. The determinant for x is (5)(5) - (-7)(-3) = 25 - 21 = 4, so x = 4/34 = 2/17. The determinant for y is 4(-3) - 2(5) = -12 - 10 = -22, so y = -22/34 = -11/17.

Use Cramer's Rule to Solve the Linear System {4x−7y=52x+5y=−3\left\{ \begin{array} { l } 4 x - 7 y = 5 \\2 x + 5 y = - 3\end{array} \right.{4x−7y=52x+5y=−3​

Use Cramer's Rule to Solve the Linear System $\left\{ \begin{array} { l } 4 x - 7 y = 5 \\2 x + 5 y = - 3\end{array} \right.$