Find the nth term of the geometric sequence.
-$4,2,1 , \frac { 1 } { 2 } , \ldots$
A) $a _ { n } = 4 \left( \frac { 1 } { 4 } \right) ^ { n - 1 }$
B) $a _ { n } = \frac { 1 } { 2 } ( 4 ) ^ { n - 1 }$
C) $a _ { n } = 4 \left( \frac { 1 } { 2 } \right) ^ { n - 1 }$
D) $a _ { n } = 4 \cdot 2 ^ { n - 1 }$

Question

Quizplus · Accepted Answer

The common ratio of the sequence is $\frac{1}{2}$, and the first term is 4. Therefore, the nth term is given by $a_n = 4 \left( \frac{1}{2} \right)^{n-1}$.

Find the Nth Term of the Geometric Sequence 4,2,1,12,…4,2,1 , \frac { 1 } { 2 } , \ldots4,2,1,21​,…

Find the Nth Term of the Geometric Sequence $4,2,1 , \frac { 1 } { 2 } , \ldots$