The sequence is defined recursively. Write the first four terms.
-$$a _ { 1 } = 135 \text { and } a _ { n + 1 } = \frac { 1 } { 3 } \left( a _ { n } \right) \text { for } n \geq 2$$

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The Answer of The sequence is defined recursively. Write the first four terms.
-$$a _ { 1 } = 135 \text { and } a _ { n + 1 } = \frac { 1 } { 3 } \left( a _ { n } \right) \text { for } n \geq 2$$

The Sequence Is Defined Recursively a1=135 and an+1=13(an) for n≥2a _ { 1 } = 135 \text { and } a _ { n + 1 } = \frac { 1 } { 3 } \left( a _ { n } \right) \text { for } n \geq 2a1​=135 and an+1​=31​(an​) for n≥2

The Sequence Is Defined Recursively $a _ { 1 } = 135 \text { and } a _ { n + 1 } = \frac { 1 } { 3 } \left( a _ { n } \right) \text { for } n \geq 2$