Solve the problem.
-A spinner has regions numbered 1 through 21. What is the probability that the spinner will stop on an even number or a multiple of 3?
A) $\frac { 10 } { 9 }$
B) 17
C) $\frac { 2 } { 3 }$
D) $\frac { 1 } { 3 }$

Question

Quizplus · Accepted Answer

The even numbers between 1 and 21 are 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20, making 10 even numbers. The multiples of 3 between 1 and 21 are 3, 6, 9, 12, 15, 18, and 21, making 7 multiples of 3. However, 6, 12, and 18 are both even and multiples of 3, so they are counted twice if we simply add the counts. To avoid double-counting, we subtract the numbers that are both even and multiples of 3, which have already been counted in the 10 even numbers. So, we have 10 (even numbers) + 4 (unique multiples of 3 that are not even) = 14 unique numbers that are either even or multiples of 3 out of 21. Therefore, the probability is $\frac{14}{21}$, which simplifies to $\frac{2}{3}$.

Solve the Problem 109\frac { 10 } { 9 }910​ B) 17 C)

Solve the Problem $\frac { 10 } { 9 }$ B) 17
C)