Solve the problem.
-A lottery game has balls numbered 1 through 19. What is the probability of selecting an even numbered ball or a 13?
A) $\frac { 9 } { 10 }$
B) $\frac { 10 } { 19 }$
C) $\frac { 9 } { 19 }$
D) $\frac { 8 } { 19 }$

Question

Quizplus · Accepted Answer

There are 9 even numbered balls (2, 4, 6, 8, 10, 12, 14, 16, 18) and one additional ball numbered 13 that meets the criteria, making 10 balls in total that satisfy the condition out of 19. Therefore, the probability is $\frac{10}{19}$.

Solve the Problem 910\frac { 9 } { 10 }109​ B) 1019\frac { 10 } { 19 }1910​

Solve the Problem $\frac { 9 } { 10 }$ B) $\frac { 10 } { 19 }$