Solve the problem.
-Given that P(A) = 0.56 and P(B) = 0.26, find P(A $P ( A \cup B )$ if A and B are mutually exclusive.
A) 0.6744
B) 0.1456
C) 0.82
D) 0

Question

Solve the problem.
-Given that P(A) = 0.56 and P(B) = 0.26, find P(A $P ( A \cup B )$  if A and B are mutually exclusive.
A) 0.6744
B) 0.1456
C) 0.82
D) 0

Quizplus · Accepted Answer

Since the problem asks for $P(A \cup B)$ but does not provide information on whether events A and B are independent or mutually exclusive, nor does it provide the intersection probability $P(A \cap B)$, the general formula for $P(A \cup B)$ is $P(A) + P(B) - P(A \cap B)$. Without additional information, we cannot accurately calculate $P(A \cap B)$, but if we assume A and B are mutually exclusive (which means $P(A \cap B) = 0$), then $P(A \cup B) = P(A) + P(B) = 0.56 + 0.26 = 0.82$. This assumption is based on the provided choices and the context of the question.

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