Solve the problem.
-In a probability model, which of the following numbers could be the probability of an outcome: $0,0.2 , - 0.01 , - \frac { 1 } { 3 } , \frac { 1 } { 2 } , \frac { 5 } { 4 } , 1,1.5$

A) $0,0.2 , - 0.01,1,1.5$

B) $0,0.2 , \frac { 1 } { 2 } , 1$

C) $0,0.2 , - 0.01 , - \frac { 1 } { 3 } , \frac { 1 } { 2 } , 1$

D) $0.2 , \frac { 1 } { 2 } , 1$

Question

Solve the problem.
-In a probability model, which of the following numbers could be the probability of an outcome: $0,0.2 , - 0.01 , - \frac { 1 } { 3 } , \frac { 1 } { 2 } , \frac { 5 } { 4 } , 1,1.5$

A) $0,0.2 , - 0.01,1,1.5$

B) $0,0.2 , \frac { 1 } { 2 } , 1$

C) $0,0.2 , - 0.01 , - \frac { 1 } { 3 } , \frac { 1 } { 2 } , 1$

D) $0.2 , \frac { 1 } { 2 } , 1$

Quizplus · Accepted Answer

In a probability model, probabilities must be between 0 and 1, inclusive. This means they can be as low as 0 (the event never happens) or as high as 1 (the event always happens), but not less than 0 or more than 1. Therefore, the valid probabilities from the given options are $0, 0.2, \frac{1}{2},$ and $1$.

Solve the Problem 0,0.2,−0.01,−13,12,54,1,1.50,0.2 , - 0.01 , - \frac { 1 } { 3 } , \frac { 1 } { 2 } , \frac { 5 } { 4 } , 1,1.50,0.2,−0.01,−31​,21​,45​,1,1.5

Solve the Problem $0,0.2 , - 0.01 , - \frac { 1 } { 3 } , \frac { 1 } { 2 } , \frac { 5 } { 4 } , 1,1.5$