Solve the problem.
-A foul tip of a baseball is hit straight upward from a height of 4 feet with an initial velocity of 112 feet per second. The function $$s ( t ) = - 16 t ^ { 2 } + 112 t + 4$$ 4 describes the ball's height above the ground, s(t), in feet, t seconds
After it was hit. The ball reaches its maximum height above the ground when the instantaneous speed reaches
Zero. After how many seconds does the ball reach its maximum height?
A) 112
B) $\frac { 3 } { 32 }$
C) $\frac { 7 } { 2 }$
D) 7

Question

Quizplus · Accepted Answer

To find the time at which the ball reaches its maximum height, we need to find the vertex of the parabola described by the equation $s(t) = -16t^2 + 112t + 4$. The time at which the maximum height occurs can be found using the formula $t = -\frac{b}{2a}$, where $a = -16$ and $b = 112$. Plugging these values in gives $t = -\frac{112}{2(-16)} = \frac{112}{32} = \frac{7}{2}$ seconds.

Solve the Problem s(t)=−16t2+112t+4s ( t ) = - 16 t ^ { 2 } + 112 t + 4s(t)=−16t2+112t+4

Solve the Problem $s ( t ) = - 16 t ^ { 2 } + 112 t + 4$