Determine whether f is continuous at c.
-$f ( x ) = \frac { - 1 } { x ^ { 2 } + 8 x } ; \quad c = - 8$
A) not continuous
B) continuous

Name: Determine whether f is continuous at c. -$f ( x ) = \frac { - 1 } { x ^ { 2 } + 8 x } ; \quad c = - 8$ A) not continuous B) continuous
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Question

Quizplus · Accepted Answer

The function $f(x) = \frac{-1}{x^2 + 8x}$ is not continuous at $c = -8$ because the denominator becomes 0 when $x = -8$, making the function undefined at that point.

Determine Whether F Is Continuous at C f(x)=−1x2+8x;c=−8f ( x ) = \frac { - 1 } { x ^ { 2 } + 8 x } ; \quad c = - 8f(x)=x2+8x−1​;c=−8

Determine Whether F Is Continuous at C $f ( x ) = \frac { - 1 } { x ^ { 2 } + 8 x } ; \quad c = - 8$