Find the limit algebraically.
-$$\lim _ { x \rightarrow 0 } \frac { 2 \sin x } { 4 x }$$
A) Does not exist
B) $\frac { 1 } { 2 }$
C) 1
D) 0

Question

Quizplus · Accepted Answer

The limit can be simplified using the well-known limit $\lim _ { x \rightarrow 0 } \frac { \sin x } { x } = 1$. Thus, $\lim _ { x \rightarrow 0 } \frac { 2 \sin x } { 4 x } = \frac { 2 } { 4 } \lim _ { x \rightarrow 0 } \frac { \sin x } { x } = \frac { 1 } { 2 }$.

Find the Limit Algebraically lim⁡x→02sin⁡x4x\lim _ { x \rightarrow 0 } \frac { 2 \sin x } { 4 x }x→0lim​4x2sinx​

Find the Limit Algebraically $\lim _ { x \rightarrow 0 } \frac { 2 \sin x } { 4 x }$