Find the limit algebraically.
-$$\lim _ { x \rightarrow 2 } \left( x ^ { 3 } + 5 x ^ { 2 } - 7 x + 1 \right)$$
A) 15
B) 0
C) 29
D) does not exist

Question

Quizplus · Accepted Answer

The limit is the value that the function approaches as x approaches 2. To find the limit, we can simply substitute x = 2 into the function:$$\lim _ { x \rightarrow 2 } \left( x ^ { 3 } + 5 x ^ { 2 } - 7 x + 1 \right) = 2 ^ { 3 } + 5 ( 2 ) ^ { 2 } - 7 ( 2 ) + 1 = 8 + 20 - 14 + 1 = 15$$Therefore, the limit is 15.

Find the Limit Algebraically lim⁡x→2(x3+5x2−7x+1)\lim _ { x \rightarrow 2 } \left( x ^ { 3 } + 5 x ^ { 2 } - 7 x + 1 \right)x→2lim​(x3+5x2−7x+1)

Find the Limit Algebraically $\lim _ { x \rightarrow 2 } \left( x ^ { 3 } + 5 x ^ { 2 } - 7 x + 1 \right)$