Find the vertex and axis of symmetry of the graph of the function.
-$f ( x ) = - x ^ { 2 } - 12 x + 2$
A) $( 6 , - 106 ) ; x = 6$
B) $( - 6,38 ) ; x = - 6$
C) $( - 12,2 ) ; x = - 12$
D) $( 6 , - 34 ) ; x = 6$

Question

Quizplus · Accepted Answer

The vertex form of a quadratic function is given by $x = -\frac{b}{2a}$. For $f(x) = -x^2 - 12x + 2$, $a = -1$ and $b = -12$. Thus, the x-coordinate of the vertex is $-\frac{-12}{2(-1)} = -6$. Substituting $x = -6$ into the function gives the y-coordinate as 38. Therefore, the vertex is $(-6, 38)$ and the axis of symmetry is $x = -6$.

Find the Vertex and Axis of Symmetry of the Graph f(x)=−x2−12x+2f ( x ) = - x ^ { 2 } - 12 x + 2f(x)=−x2−12x+2

Find the Vertex and Axis of Symmetry of the Graph $f ( x ) = - x ^ { 2 } - 12 x + 2$