Solve f(x) = g(x). Find the points of intersection of the graphs of the two functions.
-$$\begin{array} { l }
f ( x ) = x ^ { 2 } - 13 x + 36 \
g ( x ) = 2 x ^ { 2 } - 16 x + 32 \
\text {
A) } x = - \frac { \sqrt { 32 } } { 2 } , x = \frac { \sqrt { 32 } } { 2 }
\end{array}$$
B) $x = 4 , x = - 1$
C) $x = \frac { 1 } { 4 } , x = - 1$
D) $x = - \frac { \sqrt { 17 } } { 2 } , x = \frac { \sqrt { 17 } } { 2 }$

Question

Solve f(x) = g(x). Find the points of intersection of the graphs of the two functions.
-$$\begin{array} { l } 
f ( x ) = x ^ { 2 } - 13 x + 36 \
g ( x ) = 2 x ^ { 2 } - 16 x + 32 \
\text {
A) } x = - \frac { \sqrt { 32 } } { 2 } , x = \frac { \sqrt { 32 } } { 2 }
\end{array}$$
B) $x = 4 , x = - 1$
C) $x = \frac { 1 } { 4 } , x = - 1$
D) $x = - \frac { \sqrt { 17 } } { 2 } , x = \frac { \sqrt { 17 } } { 2 }$

Quizplus · Accepted Answer

To find the points of intersection, set $f(x) = g(x)$ and solve for $x$:$$x^2 - 13x + 36 = 2x^2 - 16x + 32$$Rearrange the equation to get all terms on one side:$$0 = x^2 - 3x - 4$$Factor the quadratic equation:$$0 = (x - 4)(x + 1)$$Solve for $x$:$$x = 4, x = -1$$These are the points of intersection.

Solve F(x) = G(x) B) x=4,x=−1x = 4 , x = - 1x=4,x=−1

Solve F(x) = G(x) B) $x = 4 , x = - 1$