Use factoring to find the zeros of the quadratic function. List the x-intercepts of the graph of the function.
-$$g ( x ) = 16 x ^ { 2 } - 1$$
A) $x = \frac { 1 } { 4 }$
B) $x = \frac { 1 } { 4 } , x = 0$
C) $x = - \frac { 1 } { 4 }$
D) $x = \frac { 1 } { 4 } , x = - \frac { 1 } { 4 }$

Question

Quizplus · Accepted Answer

The given quadratic function $g(x) = 16x^2 - 1$ can be factored as a difference of squares: $g(x) = (4x)^2 - 1^2 = (4x + 1)(4x - 1)$. Setting each factor equal to zero gives $4x + 1 = 0$ and $4x - 1 = 0$, which solve to $x = -\frac{1}{4}$ and $x = \frac{1}{4}$, respectively. These are the x-intercepts of the graph.

Use Factoring to Find the Zeros of the Quadratic Function g(x)=16x2−1g ( x ) = 16 x ^ { 2 } - 1g(x)=16x2−1

Use Factoring to Find the Zeros of the Quadratic Function $g ( x ) = 16 x ^ { 2 } - 1$