Solve the Problem $$\mathrm { s } = 160 \mathrm { t } - 16 \mathrm { t } ^ { 2 }$$

Solve the problem.
-A ball is thrown vertically upward with an initial velocity of 160 feet per second. The distance in feet of the ball from the ground after t seconds is $$\mathrm { s } = 160 \mathrm { t } - 16 \mathrm { t } ^ { 2 }$$ . For what interval of time is the ball more than 256 above the
Ground?

A) $\{ x \mid 1.5 \mathrm { sec } < x < 8.5 \mathrm { sec } \}$
B) $\{ x \mid 2 \sec < x < 8 \mathrm { sec } \}$
C) $\{ x \mid 4.5 \mathrm { sec } < x < 5.5 \mathrm { sec } \}$
D) $\{ x \mid 7 \sec < x < 13 \mathrm { sec } \}$