Solve the problem.
-$$x ^ { 2 } + 6 x \leq 0$$
A) $( - \infty , 0 ]$ or $[ 6 , \infty )$
B) $[ - 6,0 ]$
C) $( - \infty , - 6 ]$ or $[ 0 , \infty )$
D) $[ 0,6 ]$

Question

Quizplus · Accepted Answer

To solve the inequality $x^2 + 6x \leq 0$, factor it to get $x(x + 6) \leq 0$. The critical points are $x = 0$ and $x = -6$. Testing intervals around these points or analyzing the sign of each factor reveals that the solution is $x \in [-6, 0]$.

Solve the Problem x2+6x≤0x ^ { 2 } + 6 x \leq 0x2+6x≤0

Solve the Problem $x ^ { 2 } + 6 x \leq 0$