Find the vertical asymptotes of the rational function.
-$$h ( x ) = \frac { 6 x } { x + 2 }$$
A) x = 2
B) x = 6
C) x = -2
D) none

Question

Quizplus · Accepted Answer

Vertical asymptotes occur where the denominator of a rational function is equal to zero, as long as the numerator is not also zero at those points. For the given function $h(x) = \frac{6x}{x+2}$, setting the denominator equal to zero gives $x + 2 = 0$, which solves to $x = -2$. Therefore, $x = -2$ is the vertical asymptote.

Find the Vertical Asymptotes of the Rational Function h(x)=6xx+2h ( x ) = \frac { 6 x } { x + 2 }h(x)=x+26x​

Find the Vertical Asymptotes of the Rational Function $h ( x ) = \frac { 6 x } { x + 2 }$