Find the vertical asymptotes of the rational function.
-$$h ( x ) = \frac { x + 11 } { x ^ { 2 } - 16 x }$$
A) $x = 0 , x = - 4 , x = 4$
B) $x = 0 , x = 16$
C) $x = - 4 , x = 4$
D) $x = 16 , x = - 11$

Question

Quizplus · Accepted Answer

Vertical asymptotes occur where the denominator is zero and the numerator is not zero. The denominator $x^2 - 16x$ factors to $x(x - 16)$, so the vertical asymptotes are at $x = 0$ and $x = 16$.

Find the Vertical Asymptotes of the Rational Function h(x)=x+11x2−16xh ( x ) = \frac { x + 11 } { x ^ { 2 } - 16 x }h(x)=x2−16xx+11​

Find the Vertical Asymptotes of the Rational Function $h ( x ) = \frac { x + 11 } { x ^ { 2 } - 16 x }$