Solve the problem.
-The logistic growth functi $f ( t ) = \frac { 50,000 } { 1 + 2,499.0 e ^ { - 1.9 t } }$ models the number of people who have become ill with a particular infection t weeks after its initial outbreak in a particular community. How many people became ill
With this infection when the epidemic began?
A) 20 people
B) 2,500 people
C) 50,000 people
D) 2,499 people

Question

Quizplus · Accepted Answer

To find the number of people who became ill when the epidemic began, we set $t = 0$ in the given logistic growth function: $f(0) = \frac{50,000}{1 + 2,499.0e^{-1.9(0)}} = \frac{50,000}{1 + 2,499} = \frac{50,000}{2,500} = 20$.

Solve the Problem f(t)=50,0001+2,499.0e−1.9tf ( t ) = \frac { 50,000 } { 1 + 2,499.0 e ^ { - 1.9 t } }f(t)=1+2,499.0e−1.9t50,000​

Solve the Problem $f ( t ) = \frac { 50,000 } { 1 + 2,499.0 e ^ { - 1.9 t } }$