Solve the problem.
-In 1990, the population of a country was estimated at 4 million. For any subsequent year the population, P(t) (in millions), can be modeled by the equation $\mathrm { P } ( \mathrm { t } ) = \frac { 240 } { 5 + 54.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } }$ , where t is the number of years since 1990.
Estimate the year when the population will be 21 million.
A) approximately the year 2088
B) approximately the year 2016
C) approximately the year 2093
D) approximately the year 2041

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The Answer of Solve the problem.
-In 1990, the population of a country was estimated at 4 million. For any subsequent year the population, P(t) (in millions), can be modeled by the equation $\mathrm { P } ( \mathrm { t } ) = \frac { 240 } { 5 + 54.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } }$ , where t is the number of years since 1990.
Estimate the year when the population will be 21 million.
A) approximately the year 2088
B) approximately the year 2016
C) approximately the year 2093
D) approximately the year 2041

Solve the Problem P(t)=2405+54.99e−0.0208t\mathrm { P } ( \mathrm { t } ) = \frac { 240 } { 5 + 54.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } }P(t)=5+54.99e−0.0208t240​

Solve the Problem $\mathrm { P } ( \mathrm { t } ) = \frac { 240 } { 5 + 54.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } }$