Find the value of the expression.
-Let $\log _ { \mathrm { b } } \mathrm { A } = 2.087$ and $\log _ { \mathrm { b } } \mathrm { B } = 0.188$. Find $\log _ { \mathrm { b } } \mathrm { AB }$.
A) $0.392$
B) $11.101$
C) $1.899$
D) $2.275$

Question

Quizplus · Accepted Answer

The property of logarithms that states $\log_b(MN) = \log_b M + \log_b N$ is used here. Thus, $\log_b AB = \log_b A + \log_b B = 2.087 + 0.188 = 2.275$.

Find the Value of the Expression log⁡bA=2.087\log _ { \mathrm { b } } \mathrm { A } = 2.087logb​A=2.087

Find the Value of the Expression $\log _ { \mathrm { b } } \mathrm { A } = 2.087$