Solve the problem.
-A gear with a radius of 16 centimeters is turning at $\frac { \pi } { 11 }$ radians/sec. What is the linear speed at a point on the outer edge of the gear?
A) $\frac { 11 \pi } { 16 } \mathrm {~cm} / \mathrm { sec }$
B) $\frac { \pi } { 176 } \mathrm {~cm} / \mathrm { sec }$
C) $176 \pi \mathrm { cm } / \mathrm { sec }$
D) $\frac { 16 \pi } { 11 } \mathrm {~cm} / \mathrm { sec }$

Question

Quizplus · Accepted Answer

The linear speed $v$ at the edge of a rotating object is given by $v = r\omega$, where $r$ is the radius and $\omega$ is the angular speed. Here, $r = 16$ cm and $\omega = \frac{\pi}{11}$ radians/sec, so $v = 16 \cdot \frac{\pi}{11} = \frac{16\pi}{11}$ cm/sec.

Solve the Problem π11\frac { \pi } { 11 }11π​ Radians/sec 11π16 cm/sec\frac { 11 \pi } { 16 } \mathrm {~cm} / \mathrm { sec }1611π​ cm/sec

Solve the Problem $\frac { \pi } { 11 }$ Radians/sec $\frac { 11 \pi } { 16 } \mathrm {~cm} / \mathrm { sec }$