Solve the equation on the interval $$0 \leq \theta

Question

Solve the equation on the interval $$0 \leq \theta < 2 \pi \text {. }$$
-$\sqrt { 3 } \sin \theta - \cos \theta = - 1$
A) $\frac { 3 \pi } { 2 } , \frac { \pi } { 6 }$

B) $0 , \frac { 4 \pi } { 3 }$

C) $\frac { \pi } { 2 } , \frac { 7 \pi } { 6 }$

D) $0 , \frac { 2 \pi } { 3 }$

Quizplus · Accepted Answer

The Answer of Solve the equation on the interval $$0 \leq \theta < 2 \pi \text {. }$$
-$\sqrt { 3 } \sin \theta - \cos \theta = - 1$
A) $\frac { 3 \pi } { 2 } , \frac { \pi } { 6 }$

B) $0 , \frac { 4 \pi } { 3 }$

C) $\frac { \pi } { 2 } , \frac { 7 \pi } { 6 }$

D) $0 , \frac { 2 \pi } { 3 }$

Solve the Equation on the Interval 0≤θ<2π. 0 \leq \theta < 2 \pi \text {. }0≤θ<2π.

Solve the Equation on the Interval $0 \leq \theta < 2 \pi \text {. }$