Write the trigonometric expression as an algebraic expression containing u and v.
-$\sin \left( \tan ^ { - 1 } u + \tan ^ { - 1 } v \right)$
A) $\frac { 1 - u v } { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } }$

B) $\frac { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } } { 1 - u v }$

C) $\frac { \mathrm { u } + \mathrm { v } } { \sqrt { \mathrm { u } ^ { 2 } + 1 } \cdot \sqrt { \mathrm { v } ^ { 2 } + 1 } }$

D) $\frac { 1 + u v } { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } }$

Question

Write the trigonometric expression as an algebraic expression containing u and v.
-$\sin \left( \tan ^ { - 1 } u + \tan ^ { - 1 } v \right)$
A) $\frac { 1 - u v } { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } }$

B) $\frac { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } } { 1 - u v }$

C) $\frac { \mathrm { u } + \mathrm { v } } { \sqrt { \mathrm { u } ^ { 2 } + 1 } \cdot \sqrt { \mathrm { v } ^ { 2 } + 1 } }$

D) $\frac { 1 + u v } { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } }$

Quizplus · Accepted Answer

The Answer of Write the trigonometric expression as an algebraic expression containing u and v.
-$\sin \left( \tan ^ { - 1 } u + \tan ^ { - 1 } v \right)$
A) $\frac { 1 - u v } { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } }$

B) $\frac { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } } { 1 - u v }$

C) $\frac { \mathrm { u } + \mathrm { v } } { \sqrt { \mathrm { u } ^ { 2 } + 1 } \cdot \sqrt { \mathrm { v } ^ { 2 } + 1 } }$

D) $\frac { 1 + u v } { \sqrt { u ^ { 2 } + 1 } \cdot \sqrt { v ^ { 2 } + 1 } }$

Write the Trigonometric Expression as an Algebraic Expression Containing U sin⁡(tan⁡−1u+tan⁡−1v)\sin \left( \tan ^ { - 1 } u + \tan ^ { - 1 } v \right)sin(tan−1u+tan−1v)

Write the Trigonometric Expression as an Algebraic Expression Containing U $\sin \left( \tan ^ { - 1 } u + \tan ^ { - 1 } v \right)$