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Solve the Problem 8sin⁡2θ+9sin⁡θ+1sin⁡2θ−1\frac { 8 \sin ^ { 2 } \theta + 9 \sin \theta + 1 } { \sin ^ { 2 } \theta - 1 }

Question 171

Essay

Solve the problem.
-Factor and simplify: 8sin⁡2θ+9sin⁡θ+1sin⁡2θ−1\frac { 8 \sin ^ { 2 } \theta + 9 \sin \theta + 1 } { \sin ^ { 2 } \theta - 1 }

Correct Answer:

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