Use a graphing utility to solve the equation on the interval 0 $0 ^ { \circ } \leq x

Question

Use a graphing utility to solve the equation on the interval 0 $0 ^ { \circ } \leq x < 360 ^ { \circ }$ . Express the solution(s) rounded to one decimal
place.
-$\sin ^ { 2 } x + 8 \sin x + 16 = 0$
A) 208.2°, 331.8°
B) 28.2°, 151.8°
C) 28.2°, 151.8°, 208.2°, 331.8°
D) No solution

Quizplus · Accepted Answer

The equation $\sin^2 x + 8 \sin x + 16 = 0$ can be rewritten as $(\sin x + 4)^2 = 0$, which implies $\sin x = -4$. Since the sine function only takes values between -1 and 1, there is no solution.

Use a Graphing Utility to Solve the Equation on the Interval