Solve the equation on the interval $$0 \leq \theta

Name: Solve the equation on the interval \[0 \leq \theta < 2 \pi\] -$\sec ^ { 2 } \theta - 2 = \tan ^ { 2 } \theta$ A) $\frac { \pi } { 6 }$ B) $\frac { \pi } { 3 }$ C) $\frac { \pi } { 4 }$ D) No solution
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Question

Solve the equation on the interval $$0 \leq \theta < 2 \pi$$
-$\sec ^ { 2 } \theta - 2 = \tan ^ { 2 } \theta$
A) $\frac { \pi } { 6 }$

B) $\frac { \pi } { 3 }$

C) $\frac { \pi } { 4 }$

D) No solution

Quizplus · Accepted Answer

The Answer of Solve the equation on the interval $$0 \leq \theta < 2 \pi$$
-$\sec ^ { 2 } \theta - 2 = \tan ^ { 2 } \theta$
A) $\frac { \pi } { 6 }$

B) $\frac { \pi } { 3 }$

C) $\frac { \pi } { 4 }$

D) No solution

Solve the Equation on the Interval 0≤θ<2π0 \leq \theta < 2 \pi0≤θ<2π

Solve the Equation on the Interval $0 \leq \theta < 2 \pi$