Solve the equation on the interval [0, 2π).
-Suppose $f ( x ) = 6 \csc \theta - 1$. Solve $f ( x ) = 5$.
A) $\frac { 3 \pi } { 2 }$
B) $\pi$
C) $\frac { \pi } { 2 }$
D) $2 \pi$

Question

Quizplus · Accepted Answer

The equation $6 \csc \theta - 1 = 5$ simplifies to $6 \csc \theta = 6$, which gives $\csc \theta = 1$. This implies $\sin \theta = 1$, which occurs at $\theta = \frac{\pi}{2}$ within the interval [0, 2π).

Solve the Equation on the Interval [0, 2π) f(x)=6csc⁡θ−1f ( x ) = 6 \csc \theta - 1f(x)=6cscθ−1

Solve the Equation on the Interval [0, 2π) $f ( x ) = 6 \csc \theta - 1$