Find the exact solution of the equation.
-$$\sin ^ { - 1 } x = \frac { \pi } { 2 }$$
A) $x = 1$
B) $x = \pi$
C) $x = - 1$
D) $x = 0$

Name: Find the exact solution of the equation. -\[\sin ^ { - 1 } x = \frac { \pi } { 2 }\] A) $x = 1$ B) $x = \pi$ C) $x = - 1$ D) $x = 0$
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Question

Quizplus · Accepted Answer

The inverse sine function, $\sin^{-1}x$, gives the angle whose sine is $x$. Since $\sin\left(\frac{\pi}{2}\right) = 1$, the equation $\sin^{-1}x = \frac{\pi}{2}$ means that $x = 1$.

Find the Exact Solution of the Equation sin⁡−1x=π2\sin ^ { - 1 } x = \frac { \pi } { 2 }sin−1x=2π​

Find the Exact Solution of the Equation $\sin ^ { - 1 } x = \frac { \pi } { 2 }$