Write the complex number in polar form. Express the argument in degrees, rounded to the nearest tenth, if necessary.
-$- 6$
A) $6 \left( \cos 270 ^ { \circ } + i \sin 270 ^ { \circ } \right)$
B) $6 \left( \cos 180 ^ { \circ } + i \sin 180 ^ { \circ } \right)$
C) $6 \left( \cos 0 ^ { \circ } + i \sin 0 ^ { \circ } \right)$
D) $6 \left( \cos 90 ^ { \circ } + i \sin 90 ^ { \circ } \right)$

Question

Quizplus · Accepted Answer

The complex number $-6$ can be thought of as $-6 + 0i$, which lies on the negative x-axis in the complex plane. The angle (or argument) from the positive x-axis to this point is $180^\circ$, making the polar form $6(\cos 180^\circ + i\sin 180^\circ)$ because the magnitude is 6 and the direction is directly to the left (or at $180^\circ$).

Write the Complex Number in Polar Form −6- 6−6 A) 6(cos⁡270∘+isin⁡270∘)6 \left( \cos 270 ^ { \circ } + i \sin 270 ^ { \circ } \right)6(cos270∘+isin270∘)

Write the Complex Number in Polar Form $- 6$ A) $6 \left( \cos 270 ^ { \circ } + i \sin 270 ^ { \circ } \right)$