Find a polar equation for the conic. A focus is at the pole.
-$\mathrm { e } = \frac { 1 } { 2 } ;$ directrix is perpendicular to the polar axis 2 to the left of the pole
A) $r = \frac { 4 } { 4 - 2 \cos \theta }$
B) $r = \frac { 8 } { 4 + 2 \cos \theta }$
C) $r = \frac { 8 } { 4 - 2 \cos \theta }$
D) $r = \frac { 4 } { 4 + 2 \cos \theta }$

Question

Quizplus · Accepted Answer

The directrix is perpendicular to the polar axis 2 to the left of the pole, so the equation of the directrix is $x = -2$. The eccentricity is $e = \frac{1}{2}$, so the conic is a parabola. The focus is at the pole, so the polar equation of the parabola is $r = \frac{4}{4 - 2 \cos \theta}$.

Find a Polar Equation for the Conic e=12;\mathrm { e } = \frac { 1 } { 2 } ;e=21​;

Find a Polar Equation for the Conic $\mathrm { e } = \frac { 1 } { 2 } ;$