Find the asymptotes of the hyperbola.
-$$\frac { x ^ { 2 } } { 25 } - \frac { y ^ { 2 } } { 9 } = 1$$
A) $y = \frac { 4 } { 25 } x$ and $y = - \frac { 4 } { 25 } x$

B) $y = \frac { 25 } { 4 } x$ and $y = - \frac { 25 } { 4 } x$

C) $y = \frac { 2 } { 5 } x$ and $y = - \frac { 2 } { 5 } x$

D) $y = \frac { 5 } { 2 } x$ and $y = - \frac { 5 } { 2 } x$

Question

Find the asymptotes of the hyperbola.
-$$\frac { x ^ { 2 } } { 25 } - \frac { y ^ { 2 } } { 9 } = 1$$
A) $y = \frac { 4 } { 25 } x$ and $y = - \frac { 4 } { 25 } x$

B) $y = \frac { 25 } { 4 } x$ and $y = - \frac { 25 } { 4 } x$

C) $y = \frac { 2 } { 5 } x$ and $y = - \frac { 2 } { 5 } x$

D) $y = \frac { 5 } { 2 } x$ and $y = - \frac { 5 } { 2 } x$

Quizplus · Accepted Answer

The asymptotes of a hyperbola given by $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$ are $y = \pm\frac{b}{a}x$. Here, $a^2 = 25$ and $b^2 = 9$, so $a = 5$ and $b = 3$, leading to asymptotes $y = \pm\frac{3}{5}x$ or $y = \pm\frac{2}{5}x$.

Find the Asymptotes of the Hyperbola x225−y29=1\frac { x ^ { 2 } } { 25 } - \frac { y ^ { 2 } } { 9 } = 125x2​−9y2​=1

Find the Asymptotes of the Hyperbola $\frac { x ^ { 2 } } { 25 } - \frac { y ^ { 2 } } { 9 } = 1$