SCENARIO 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force
necessary to produce cracks in stressed oak furniture.She performs a two-tail test of the null
hypothesis that the mean for the stressed oak furniture is 650.The calculated value of the Z test
statistic is a positive number that leads to a p-value of 0.080 for the test.
-True or False: Referring to Scenario 9-6, suppose the engineer had decided that the alternative
hypothesis to test was that the mean was greater than 650.Then if the test is performed with a
level of significance of 0.05, the null hypothesis would be rejected.

Question

Quizplus · Accepted Answer

The p-value (0.080) is greater than the level of significance (0.05), so the null hypothesis would not be rejected if the test were performed with a level of significance of 0.05. However, if the alternative hypothesis were that the mean was greater than 650, then the p-value would be the same (0.080), but the critical value for a one-tailed test with a level of significance of 0.05 is 1.645. Since the calculated value of the Z test statistic is a positive number, it would be greater than the critical value, and the null hypothesis would be rejected.

SCENARIO 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested