The data in the following table represent heights of students at a highschool. Find the value of the missing entry. $\begin{array}{c|c}
\begin{array}{c}
\text { Height } \
\text { (centimeters) }
\end{array} & \begin{array}{l}
\text { Relative } \
\text { frequency }
\end{array} \
\hline \text { 142-under 152 } & 0.03 \
\text { 152-under 162 } & 0.21 \
\text { 162-under 172 } & 0.27 \
172 \text {-under 182 } & 0.28 \
182 \text {-under 192 } & \
192 \text {-under 202 } & 0.02
\end{array}$
A)$19 \%$
B) $0.19$
C) $0.21$
D) The value cannot be determined from the given data.

Question

The data in the following table represent heights of students at a highschool. Find the value of the missing entry. $\begin{array}{c|c}
\begin{array}{c}
\text { Height } \
\text { (centimeters) }
\end{array} & \begin{array}{l}
\text { Relative } \
\text { frequency }
\end{array} \
\hline \text { 142-under 152 } & 0.03 \
\text { 152-under 162 } & 0.21 \
\text { 162-under 172 } & 0.27 \
172 \text {-under 182 } & 0.28 \
182 \text {-under 192 } & \
192 \text {-under 202 } & 0.02
\end{array}$  
A)$19 \%$
B) $0.19$
C) $0.21$
D) The value cannot be determined from the given data.

Quizplus · Accepted Answer

The sum of the relative frequencies should equal 1. Adding the given frequencies: 0.03 + 0.21 + 0.27 + 0.28 + 0.02 = 0.81. Therefore, the missing value is 1 - 0.81 = 0.19.

The Data in the Following Table Represent Heights of Students