The following contingency table provides a joint frequency distribution for the popular votes cast in the presidential election by region and political party. Data are in thousands, rounded to the nearest thousand. If a person who voted in the presidential election is selected at random, $\mathrm { P } \left( \mathrm { P } _ { 2 } \mid \mathrm { R } _ { 1 } \right) = 0.553$. Interpret this probability in terms of percentages.

Question

The following contingency table provides a joint frequency distribution for the popular votes cast in the presidential election by region and political party. Data are in thousands, rounded to the nearest thousand.    If a person who voted in the presidential election is selected at random, $\mathrm { P } \left( \mathrm { P } _ { 2 } \mid \mathrm { R } _ { 1 } \right) = 0.553$. Interpret this probability in terms of percentages.

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The Answer of The following contingency table provides a joint frequency distribution for the popular votes cast in the presidential election by region and political party. Data are in thousands, rounded to the nearest thousand.    If a person who voted in the presidential election is selected at random, $\mathrm { P } \left( \mathrm { P } _ { 2 } \mid \mathrm { R } _ { 1 } \right) = 0.553$. Interpret this probability in terms of percentages.

The Following Contingency Table Provides a Joint Frequency Distribution for the Popular