Find the standard deviation for the given data. Round your answer to one more decimal place than the original data.
-Christine is currently taking college astronomy. The instructor often gives quizzes. On the past seven quizzes, Christine got the following scores: $$\begin{array} { l l l l l l l }
44 & 17 & 39 & 24 & 18 & 53 & 68
\end{array}$$
A)19.1
B)9881.3
C)39
D)12,079

Question

Find the standard deviation for the given data. Round your answer to one more decimal place than the original data.
-Christine is currently taking college astronomy. The instructor often gives quizzes. On the past seven quizzes, Christine got the following scores: $$\begin{array} { l l l l l l l } 
44 & 17 & 39 & 24 & 18 & 53 & 68
\end{array}$$
A)19.1
B)9881.3
C)39
D)12,079

Quizplus · Accepted Answer

To find the standard deviation, first calculate the mean (average) of the scores: $(44 + 17 + 39 + 24 + 18 + 53 + 68) / 7 = 263 / 7 = 37.5714$. Then, for each score, subtract the mean and square the result, sum these squared differences, divide by the number of scores, and finally take the square root. The calculation gives a standard deviation of approximately 19.1 when rounded to one more decimal place than the original data.

Find the Standard Deviation for the Given Data 44173924185368\begin{array} { l l l l l l l } 44 & 17 & 39 & 24 & 18 & 53 & 68\end{array}44​17​39​24​18​53​68​

Find the Standard Deviation for the Given Data $\begin{array} { l l l l l l l } 44 & 17 & 39 & 24 & 18 & 53 & 68\end{array}$