In a certain lottery, 5 different numbers between 1 and 9 inclusive are drawn. These are the winning numbers. How many different selections are possible? Assume that the order in which the
Numbers are drawn is not important.
A)126
B)59,049
C)15,120
D)120

Question

Quizplus · Accepted Answer

The number of different selections possible is calculated using combinations since the order does not matter. The formula for combinations is C(n, r) = n! / [r!(n-r)!], where n is the total number of items, and r is the number of items to choose. Here, n=9 (numbers 1 through 9) and r=5 (choosing 5 numbers). So, C(9, 5) = 9! / [5!(9-5)!] = 9! / (5!4!) = (9*8*7*6) / (4*3*2*1) = 126.

In a Certain Lottery, 5 Different Numbers Between 1 and 9