Solve the formula for the specified variable.
-$A = \frac { 1 } { 2 } h \left( b _ { 1 } + b _ { 2 } \right) ; \quad$ for $b _ { 1 }$
A) $b _ { 1 } = \frac { h \left( b _ { 2 } \right) - 2 A } { h }$

B) $b _ { 1 } = \frac { A - h \left( b _ { 2 } \right) } { 2 h }$

C) $b _ { 1 } = \frac { \left( b _ { 2 } \right) 2 \mathrm {~A} - \mathrm { h } } { \mathrm { h } }$

D) $b _ { 1 } = \frac { 2 \mathrm {~A} - ( \mathrm { h } ) \left( \mathrm { b } _ { 2 } \right) } { \mathrm { h } }$

Question

Solve the formula for the specified variable.
-$A = \frac { 1 } { 2 } h \left( b _ { 1 } + b _ { 2 } \right) ; \quad$ for $b _ { 1 }$
A) $b _ { 1 } = \frac { h \left( b _ { 2 } \right) - 2 A } { h }$

B) $b _ { 1 } = \frac { A - h \left( b _ { 2 } \right) } { 2 h }$

C) $b _ { 1 } = \frac { \left( b _ { 2 } \right) 2 \mathrm {~A} - \mathrm { h } } { \mathrm { h } }$

D) $b _ { 1 } = \frac { 2 \mathrm {~A} - ( \mathrm { h } ) \left( \mathrm { b } _ { 2 } \right) } { \mathrm { h } }$

Quizplus · Accepted Answer

To solve for $b_1$, first multiply both sides by 2 to get rid of the fraction: $2A = h(b_1 + b_2)$. Then, isolate $b_1$ by subtracting $hb_2$ from both sides: $b_1 = \frac{2A - hb_2}{h}$.

Solve the Formula for the Specified Variable A=12h(b1+b2);A = \frac { 1 } { 2 } h \left( b _ { 1 } + b _ { 2 } \right) ; \quadA=21​h(b1​+b2​);

Solve the Formula for the Specified Variable $A = \frac { 1 } { 2 } h \left( b _ { 1 } + b _ { 2 } \right) ; \quad$