Solve the problem.
-Which is greater, E or P, and by how much? $$\begin{array} { l }
E = 1 + 3 + 5 + 7 + \ldots + 95 \
P = 2 + 4 + 6 + 8 + \ldots + 96
\end{array}$$
A) $E$ is greater by 47
B) $P$ is greater by 48
C) E is greater by 48
D) $P$ is greater by 49

Question

Solve the problem.
-Which is greater, E or P, and by how much? $$\begin{array} { l } 
E = 1 + 3 + 5 + 7 + \ldots + 95 \
P = 2 + 4 + 6 + 8 + \ldots + 96
\end{array}$$
A) $E$ is greater by 47
B) $P$ is greater by 48
C) E is greater by 48
D) $P$ is greater by 49

Quizplus · Accepted Answer

P is greater by 48 because both sequences are arithmetic series, but P starts at 2 and goes up to 96 in even steps, while E starts at 1 and goes up to 95 in odd steps. Each term in P is exactly 1 greater than the corresponding term in E, and there are 48 terms in total, making P greater by 48.

Solve the Problem E=1+3+5+7+…+95P=2+4+6+8+…+96\begin{array} { l } E = 1 + 3 + 5 + 7 + \ldots + 95 \\P = 2 + 4 + 6 + 8 + \ldots + 96\end{array}E=1+3+5+7+…+95P=2+4+6+8+…+96​

Solve the Problem $\begin{array} { l } E = 1 + 3 + 5 + 7 + \ldots + 95 \\P = 2 + 4 + 6 + 8 + \ldots + 96\end{array}$