Solve the problem.
-Find the equation of the line through $( 1,0 )$ and perpendicular to $y = 5 x + 3$.
A) $y = \frac { 1 } { 5 } x - \frac { 1 } { 5 }$
B) $y = - \frac { 1 } { 5 } x + \frac { 1 } { 3 }$
C) $y = 5 x - 3$
D) $y = - \frac { 1 } { 5 } x + \frac { 1 } { 5 }$

Question

Quizplus · Accepted Answer

The slope of the line $y = 5x + 3$ is 5. A line perpendicular to it will have a slope of $-\frac{1}{5}$. Using the point-slope form with point $(1,0)$, the equation is $y = -\frac{1}{5}x + \frac{1}{5}$.

Solve the Problem (1,0)( 1,0 )(1,0) And Perpendicular To y=5x+3y = 5 x + 3y=5x+3

Solve the Problem $( 1,0 )$ And Perpendicular To $y = 5 x + 3$