Construct a truth table for the statement.
-$\sim((w \wedge \mathrm{q}) \vee \mathrm{S})$
A)
$\begin{array}{cccc}
\mathrm{w} & \mathrm{q} & \mathrm{s} & \sim((\mathrm{w} \wedge \mathrm{q}) \vee \mathrm{s}) \
\hline \mathrm{T} & \mathrm{T} & \mathrm{T} & \mathrm{T} \
\mathrm{T} & \mathrm{T} & \mathrm{F} & \mathrm{F} \
\mathrm{T} & \mathrm{F} & \mathrm{T} & \mathrm{T} \
\mathrm{T} & \mathrm{F} & \mathrm{F} & \mathrm{F} \
\mathrm{F} & \mathrm{T} & \mathrm{T} & \mathrm{T} \
\mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{F} \
\mathrm{F} & \mathrm{F} & \mathrm{T} & \mathrm{T} \
\mathrm{F} & \mathrm{F} & \mathrm{F} & \mathrm{F}
\end{array}$
B)$\begin{array}{cccc}
\mathrm{w} & \mathrm{q} & \mathrm{s} & \sim((\mathrm{w} \wedge \mathrm{q}) \vee \mathrm{s}) \
\hline \mathrm{T} & \mathrm{T} & \mathrm{T} & \mathrm{F} \
\mathrm{T} & \mathrm{T} & \mathrm{F} & \mathrm{F} \
\mathrm{T} & \mathrm{F} & \mathrm{T} & \mathrm{F} \
\mathrm{T} & \mathrm{F} & \mathrm{F} & \mathrm{T} \
\mathrm{F} & \mathrm{T} & \mathrm{T} & \mathrm{F} \
\mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T} \
\mathrm{F} & \mathrm{F} & \mathrm{T} & \mathrm{F} \
\mathrm{F} & \mathrm{F} & \mathrm{F} & \mathrm{T}
\end{array}$

Question

Quizplus · Accepted Answer

The correct truth table for $\sim((w \wedge q) \vee s)$ reflects the negation of the disjunction between $w \wedge q$ and $s$. The output is false when either $w \wedge q$ is true or $s$ is true, and true otherwise, as shown in option B.

Construct a Truth Table for the Statement ∼((w∧q)∨S)\sim((w \wedge \mathrm{q}) \vee \mathrm{S})∼((w∧q)∨S)

Construct a Truth Table for the Statement $\sim((w \wedge \mathrm{q}) \vee \mathrm{S})$