Find the requested probability.
-A box contains the following mixture of colored marbles: 2 black, 3 red, 2 yellow, and 1 green. What is the probability of drawing a red marble followed by a green marble if the two marbles are Drawn without replacement?
A) $\frac { 1 } { 56 }$
B) $\frac { 3 } { 64 }$
C) $\frac { 3 } { 56 }$
D) $\frac { 3 } { 28 }$

Question

Find the requested probability.
-A box contains the following mixture of colored marbles: 2 black, 3 red, 2 yellow, and 1 green. What is the probability of drawing a red marble followed by a green marble if the two marbles are Drawn without replacement? 
A) $\frac { 1 } { 56 }$
B) $\frac { 3 } { 64 }$
C) $\frac { 3 } { 56 }$
D) $\frac { 3 } { 28 }$

Quizplus · Accepted Answer

The probability of drawing a red marble first is $\frac{3}{8}$ (since there are 3 red marbles out of 8 total marbles). After drawing a red marble, there are 7 marbles left, and the probability of then drawing the green marble is $\frac{1}{7}$. Multiplying these probabilities gives the overall probability of this sequence of events: $\frac{3}{8} \times \frac{1}{7} = \frac{3}{56}$.

Find the Requested Probability 156\frac { 1 } { 56 }561​

Find the Requested Probability $\frac { 1 } { 56 }$